In Fig. 38, AX bisects ∠BAC as well as ∠BDC. State the three facts needed to ensure that ∆ ABD ≅ ∆ ACD.

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Solution

$As per the given conditions,∠CAD=∠BAD and ∠CDA=∠BDA (because AX bisects ∠BAC ) AD=DA (common) Therefore, by ASA, △ACD≅△ABD$

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In Fig. 38, AX bisects ∠BAC as well as ∠BDC. State the three facts needed to ensure that ∆ ABD ≅ ∆ ACD.

As per the given conditions,∠CAD=∠BADand ∠CDA=∠BDA (because AX bisects ∠BAC )AD=DA (common)Therefore, by ASA, △ACD≅△ABD

$As per the given conditions,∠CAD=∠BAD and ∠CDA=∠BDA (because AX bisects ∠BAC ) AD=DA (common) Therefore, by ASA, △ACD≅△ABD$