Question

In Fig. 39, AO = OB and ∠A = ∠B.


(i) Is ∆ AOC ≅ ∆ BOD?
(ii) State the matching pair you have used, which is not given in the question.
(iii) Is it true to say that ∠ACO = ∠BDO?

Answer 1

We have
$$\begin{gathered} \text{∠OAC =∠OBD, AO = OB} \\ \text{Also, ∠AOC = ∠BOD (Opposite angles on same vertex)} \\ \text{Therefore, by ASA △AOC ≅△BOD} \end{gathered}$$