Question

In Fig. 4.145, if AB ⊥ BC, DC ⊥ BC and DE ⊥ AC, prove that ∆CED ∼ ∆ABC.

Answer 1

It is given that , and .

We have to prove that .

Now,

,, so.

In ∆ABC and ∆CED,

(Given)

$\angle A=\angle ECD$ ( Alternate angles)

So, (AA similarly rule)