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Angles in Same Segment of a Circle

In Fig. 4.58,...

Question

In Fig. 4.58, ∆ABC is a triangle such that $\frac{AB}{AC} = \frac{BD}{DC}, ∠ B = 70 °, ∠ C = 50 °$ . Find the ∠BAD.

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Solution

It is given that in , , and .

We have to find .

In ,

Since , therefore, AD is the bisector of $∠ A$ .

Hence,

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Similar questions

In Fig. 7.58, $Δ A B C$ is a triangle such that $\frac{A B}{A C} = \frac{B D}{D C}, ∠ B = 70^{\circ}, ∠ C = 50^{\circ}$ . Find $∠ B A D$ .

Q. In ∆ABC, it is given that

\frac{A B}{A C} = \frac{B D}{D C} . If ∠ B = 70 ° and ∠ C = 50 °, then ∠ B A D = ?

(a) 30°
(b) 40°
(c) 45°
(d) 50°

Q. In ∆ABC (Fig. 4.59), if ∠1 = ∠2, prove that

\frac{AB}{AC} = \frac{BD}{DC}

Δ A B C

, if point D is on the BC such that

\frac{A B}{A C} = \frac{B D}{D C}

∠ B = 70^{\circ}, ∠ C = 50^{\circ}

∠ B A D

Q. ∆ABC is a right triangle right-angled at A and AD ⊥ BC. Then,

\frac{BD}{DC} =

{(\frac{AB}{AC})}^{2}

\frac{AB}{AC}

{(\frac{AB}{AD})}^{2}

\frac{AB}{AD}

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