In Fig. 42, ABCD is a parallelogram in which AD = 21 cm, DH =18 cm and DK = 27 cm.
The length of AB is

(a) 63 cm (b) 63.5 cm (c) 31.5 cm (d) 31 cm

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Solution

Area of a parallelogram = Base $×$ Height
$A B \times D H = A D \times D K \Rightarrow A B \times 18 = 21 \times 27 \Rightarrow A B = \frac{21 \times 27}{18} = \frac{63}{2} = 31.5 cm$
Hence, the correct option is (c).

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In Fig. 42, ABCD is a parallelogram in which AD = 21 cm, DH =18 cm and DK = 27 cm. The length of AB is (a) 63 cm (b) 63.5 cm (c) 31.5 cm (d) 31 cm

Area of a parallelogram = Base × Height AB×DH=AD×DK⇒AB×18=21×27⇒AB=21×2718=632=31.5 cm Hence, the correct option is (c).

In Fig. 42, ABCD is a parallelogram in which AD = 21 cm, DH =18 cm and DK = 27 cm.
The length of AB is

(a) 63 cm (b) 63.5 cm (c) 31.5 cm (d) 31 cm

Area of a parallelogram = Base $×$ Height
$A B \times D H = A D \times D K \Rightarrow A B \times 18 = 21 \times 27 \Rightarrow A B = \frac{21 \times 27}{18} = \frac{63}{2} = 31.5 cm$
Hence, the correct option is (c).