Question

In Fig $6.9$, $\angle 1=\angle 2$ and $\Delta NSQz\Delta MTR$, then prove that $\Delta PTS-\Delta PRQ$

Answer 1

REF.Image

In the triangles PTS and PQR.

Let us assume that Q= angle 3 and R= angle 4.

So, angle 1 = angle 3

(corresponding angles)

and angle 2 = angle 4

Angle P is common angle

By AAA similarity triangle PTS is similar to triangle PRS.

Hence proved.