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Question

In Fig. 7.140, AB=90 and BDAC. If AB = 5.7 cm, BD = 3.8 cm and CD=5.4 cm, find BC.

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Solution

In triangleABC and triangleADB
angleABC =angle ADB (right angle)
angleBAD = angleBAC (common angle)

180 - (angleABC + angleBAC ) = 180 - (angle ADB +angleBAD ​)
angleDBA = angleBCA (proved)
Hence both the triangles are similar.
fraction numerator A B over denominator A C end fraction equals fraction numerator B D over denominator B C end fraction equals fraction numerator A D over denominator A B end fraction (Corresponding sides of similar triangles)
fraction numerator 3.8 over denominator B C end fraction equals fraction numerator A D over denominator 5.7 end fractionB C space equals fraction numerator 3.8 space cross times 5.7 over denominator A D end fractionB C space equals fraction numerator begin display style 3.8 space cross times 5.7 end style over denominator begin display style square root of A B squared minus B D squared end root end style end fraction equals fraction numerator begin display style 3.8 space cross times 5.7 end style over denominator begin display style square root of 5.7 squared minus 3.8 squared end root end style end fraction equals fraction numerator begin display style 3.8 space cross times 5.7 end style over denominator begin display style 18.05 end style end fraction equals fraction numerator 21.66 over denominator 18.05 end fraction space equals 1.2

BC = 1.2 cm


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