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Question
In Fig. 7.142, if AB⊥BC,DE⊥BC and DE⊥AC, prove that ΔCED∼ΔABC.
In Fig. 7.142, if AB⊥BC,DE⊥BC and DE⊥AC, prove that ΔCED∼ΔABC.
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Solution
AB || DC
1 =
5 (alternate interior angles)
2 = 
6 (right angles)
Hence 
ABC and 
CED are similar by AA criteria.
AB || DC
1 =5 (alternate interior angles)
2 = 6 (right angles)
Hence ABC and CED are similar by AA criteria.
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