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Converse of Basic Proportionality Theorem

In Fig. 7, AB...

Question

In Fig. 7, AB $⊥$ BC, FG $⊥$ BC and DE $⊥$ AC. Prove that Δ ADE $~$ ΔGCF

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Solution

In the given figure, we have

Then we have to prove that

The following diagram is given

In, we have

…… (1)

In, we have

…… (2)

From equation (1) and equation (2), we have

Similarly, we have

Since and are equiangular, therefore

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Converse of Basic Proportionality Theorem

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