In Fig. 8.62, there are two concetric circles with centre O of radii 5 cm and 3 cm. From an external point P, tangents PA and PB are drawn to these circles. If AP=12 cm, find the length of BP.
Sol:
In ΔOAP is a right angle at A then OP2 = OA2 + AP2
OA = 5 cm, OB = 3 cm and AP = 12 cm
OP2 = 52 + 122 = 25 + 144 = 169
OP = 13 cm
In ΔOBP is a right angle at A then OP2 = OB2 + BP2
169 = 9 + BP2
BP2 = 160
BP = 4√10 cm.
∴ length of BP = 4√10 cm.