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Question

In Fig. 98, if AB is parallel to CO and EF is a transversal, then x =
(a) 19
(b) 29
(c) 39
(d) 49

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Solution

Let the line EF intersect AB and CD at P and Q respectively.


Since, AB || CD
∴ ∠BPQ + ∠PQD = 180 (Angles on the same side of a transversal line are supplementary)
⇒ (7x − 12) + (4x + 17) = 180
⇒ 7x − 12 + 4x + 17 = 180
⇒ 11x + 5 = 180
⇒ 11x = 175
⇒ x = 15.90

Disclaimer: No option is correct.

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