In Fig., AB and CD are parallel lines intersected by a transversal PQ at L and M respectively. If ∠LMD = 35° find ∠ALM and ∠PLA.

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Solution

In the given Fig., AB || CD.
$∠ ALM = ∠ LMD = 35 ° (Alternate interior angles) Since ∠ PLA + ∠ ALM = 180 ° (Linear pair) ∴ ∠ PLA = 180 ° - 35 ° = 145 °$

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In Fig., AB and CD are parallel lines intersected by a transversal PQ at L and M respectively. If ∠LMD = 35° find ∠ALM and ∠PLA.

In the given Fig., AB || CD. ∠ALM=∠LMD=35° Alternate interior anglesSince ∠PLA+∠ALM=180° Linear pair∴∠PLA=180°-35°=145°

In the given Fig., AB || CD.
$∠ ALM = ∠ LMD = 35 ° (Alternate interior angles) Since ∠ PLA + ∠ ALM = 180 ° (Linear pair) ∴ ∠ PLA = 180 ° - 35 ° = 145 °$