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Question

In fig AB=CF,EF=BD and AFE=CBD prove that
AFE=CBD
AE=CD
1023189_ab59846a532549b4b159d13b28eefd44.png

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Solution

In ΔAFE
AF=ACCF=ACAB(1) [AB=CF is given]
In ΔCBD
CB=CABA(2)
From (1) and (2)
AF=CBI
Now in ΔAFE and ΔCBD
,EF=DB [Given}AFE=CBD [Given]
AF=CB [From I]
ΔAFEΔCBD
Thus Corresponding side of these triangles are equal
AE=CD

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