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Question

In Fig. ABC is a right angled triangle in which A=90, AB = 21 cm and AC = 28 cm. Semi - circles are described on AB, BC and AC as diameters. Find the area if the shaded region.


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Solution

In right ΔABC, by Pythagoras theorem:

BC2=AB2+AC2

BC2=212+282

BC2=352

BC=35 cm

Area of ABC=AB×AC2=21×282=294 cm2

Area of Semicircle of diameter BC = 12×227×352×352=481.25 cm2

Area of Semicircle of diameter AB = 12×227×212×212=173.25 cm2

Area of Semicircle of diameter AC = 12×227×282×282=308 cm2

Area of the shaded region
= Area of Semicircle of diameter AB + Area of Semicircle of diameter AC + Area of ΔABC - Area of Semicircle of diameter BC
= 173.25 + 308 + 294 - 481.25 = 294 cm2


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