In Fig. ABC is a right angled triangle in which ∠A=90∘, AB = 21 cm and AC = 28 cm. Semi - circles are described on AB, BC and AC as diameters. Find the area if the shaded region.
In right ΔABC, by Pythagoras theorem:
BC2=AB2+AC2
BC2=212+282
BC2=352
BC=35 cm
Area of △ABC=AB×AC2=21×282=294 cm2
Area of Semicircle of diameter BC = 12×227×352×352=481.25 cm2
Area of Semicircle of diameter AB = 12×227×212×212=173.25 cm2
Area of Semicircle of diameter AC = 12×227×282×282=308 cm2
Area of the shaded region
= Area of Semicircle of diameter AB + Area of Semicircle of diameter AC + Area of ΔABC - Area of Semicircle of diameter BC
= 173.25 + 308 + 294 - 481.25 = 294 cm2