In fig. ABCD is a parallelogram with $A B = 16$ cm. The altitudes AM and CN are respectively $6$ cm and $8$ cm, then AD is equal to :

3 c m

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6 c m

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12 c m

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16 c m

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Solution

The correct option is B $12 c m$
Area $∥$ gm $A B C D = A B \times A M = 16 \times 6 = 96 {c m}^{2}$
Again, area $∥ g m A B C D = A D \times C N = A D \times 8$
$\Rightarrow A D \times 8 = 96 \Rightarrow A D = 12 c m$

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In fig. ABCD is a parallelogram with AB=16 cm. The altitudes AM and CN are respectively 6 cm and 8 cm, then AD is equal to :

The correct option is B 12cmArea ∥gm ABCD=AB×AM=16×6=96cm2Again, area ∥gmABCD=AD×CN=AD×8⇒AD×8=96⇒AD=12cm

In fig. ABCD is a parallelogram with $A B = 16$ cm. The altitudes AM and CN are respectively $6$ cm and $8$ cm, then AD is equal to :

The correct option is B $12 c m$
Area $∥$ gm $A B C D = A B \times A M = 16 \times 6 = 96 {c m}^{2}$
Again, area $∥ g m A B C D = A D \times C N = A D \times 8$
$\Rightarrow A D \times 8 = 96 \Rightarrow A D = 12 c m$