Question

In Fig $ABCD$ is a rhombus in which $\alpha ABC={56}^o$. Which is the measure of $\angle ACD$?

Answer 1

$\angle ABC={56}^o$

$\angle BCD=180-\angle ABC$

$={180}^o-56={124}^o$

Diagonals of a rhombus bisect the interior angles

$\angle ACD$

$=\angle BCD/2=\frac{124}{2}={62}^o$