wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In Fig. AC = AE, AB = AD and BAD = EAC. Prove that BC = DE.
[2 MARKS]

i12


Open in App
Solution

We have,

BAD = EAC

Then,
BAD + DAC = EAC + DAC (0.5 Mark)
[Adding DAC to both sides]

BAC = DAE ---- (i) (0.5 Mark)

Now, In ΔABC and ΔADE,
AB = AD [Given]
BAC = DAE [From (i)]
and, AC = AE [Given]

So,
ΔABC ΔADE [SAS congruence criterion] (0.5 Mark)

BC = DE [ C.P.C.T ] (0.5 Mark)

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Similar Triangles
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon