In Fig. an object of mass M is kept on a rough table as seen from above. Forces are applied on it as shown. Find the direction of static friction if the object does not move.
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Solution
Here limiting value of friction force flim=μsN=0.4×10×10=40N The resuttant of exrernal force acting on the block Fnet=√(15)2+(20)2=25N If the block is at rest,f=Fnet=25N As f<flim. Here actual friction force acting on the block is less than flim. The friction in this case is of static nature. For the direction of friction force, we draw the free body diagram of find the resultant force. The direction of static friction is opposite to the direction of the resultant force FR. Its magnitude is equal to 25 N at angle, tanθ=1520=34 or θ=370 as shown in Fig 7.19.