The correct option is B 56∘
Given: ∠ABP=∠ACQ
By linear pair property,
∠ABP+∠ABC=180∘ ⋅⋅⋅ (i)
∠ACQ+∠ACB=180∘ ⋅⋅⋅ (ii)
From (i) and (ii),
∠ABP+∠ABC=∠ACQ+∠ACB
[∵ ∠ABP=∠ACQ ]
So, ∠ABC=∠ACB
In ΔABC,
∠ABC+∠ACB+∠BAC=180∘
⇒2∠ABC=180∘−68∘
[∵∠ABC=∠ACB]
⇒2∠ABC=112∘
⇒∠ABC=56∘