In fig ∠C=90∘ and D is the mid point of seg AC. write
tan∠ABCtan∠DBC
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Solution
In the given figure, ∠C=90∘ In △ABC, tan∠ABC=PB=ACBC In △CDB, tan∠DBC=PB=CDBC Now, tan∠ABCtan∠DBC=ACBCCDBC tan∠ABCtan∠DBC=ACCD tan∠ABCtan∠DBC=2CD2CD tan∠ABCtan∠DBC=2 (D is mid point of AC)