Question

In Fig. $\angle$E $>$$\angle$A and $\angle$C $>$$\angle$D. Prove that AD $>$EC. [2 MARKS]

Answer 1

Concept : 1 Mark
Proof : 1 Mark

In $△$ABE, it is given that

$\angle$E $>$ $\angle$A

$\Rightarrow$ AB $>$ BE .....(i)

In $△$BCD, it is given that

$\angle$C $>$ $\angle$D

$\Rightarrow$ BD $>$ BC .....(ii)


Adding (i) and (ii), We get

AB + BD $>$ BE + BC $\Rightarrow$ AD $>$ EC