In fig., $∠$ E $>$ $∠$ A and $∠$ C $>$ $∠$ D. Prove that AD $>$ EC.

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Solution

In $△$ ABE, it is given that

$∠$ E $>$ $∠$ A

$\Rightarrow$ AB $>$ BE .....(i)

In $△$ BCD, it is given that

$∠$ C $>$ $∠$ D

$\Rightarrow$ BD $>$ BC .....(ii)

Adding (i) and (ii), We get

AB + BD $>$ BE + BC $\Rightarrow$ AD $>$ EC

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