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Standard XII

Physics

Potentiometer

In fig. batte...

Question

In fig. battery $E$ is balanced on $55 c m$ length of potentiometer wire but when a resistance of $10 o h m$ is connected in parallel with the battery then it balances on $50 c m$ length of the potentiometer wire then internal resistance $r$ of the battery is

1 o h m

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3 o h m

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10 o h m

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5 o h m

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Solution

The correct option is A $1 o h m$
According to the data given in the question;

$r = (\frac{l_{1} - l_{2}}{l_{2}}) \times R^{^{'}} \Rightarrow r = (\frac{55 - 50}{50}) \times 10 = 1 Ω$

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In fig. battery E is balanced on 55 cm length of potentiometer wire but when a resistance of 10 ohm is connected in parallel with the battery then it balances on 50 cm length of the potentiometer wire then internal resistance r of the battery is

The correct option is A 1 ohmAccording to the data given in the question;r=(l1−l2l2)×R′⇒r=(55−5050)×10=1Ω

In fig. battery $E$ is balanced on $55 c m$ length of potentiometer wire but when a resistance of $10 o h m$ is connected in parallel with the battery then it balances on $50 c m$ length of the potentiometer wire then internal resistance $r$ of the battery is

The correct option is A $1 o h m$
According to the data given in the question;

$r = (\frac{l_{1} - l_{2}}{l_{2}}) \times R^{^{'}} \Rightarrow r = (\frac{55 - 50}{50}) \times 10 = 1 Ω$