Question

In fig, $PQ\parallel XY$ and $\angle 1={110}^o,\angle 8={70}^o$. Then find $\angle 3$ and $\angle 6$

• A. $\angle 3={60}^o,\angle 6={120}^o$
• B. $\angle 3={110}^o,\angle 6={70}^o$
• C. $\angle 3={100}^o,\angle 6={80}^o$
• D. $\angle 3={90}^o,\angle 6={90}^o$

Answer 1

The correct option is B $\angle 3={110}^o,\angle 6={70}^o$

$\because PQ\parallel XY$
and AB is transversal
$\therefore \angle 1=\angle 3$ (vertically opposite angle)
$\angle 1={110}^o$ (given)
$\therefore \angle 3={110}^o$
Again,
$\angle 6=\angle 8$ (vertically opposite
$\angle 8={60}^o$ (given)
$\therefore \angle 6={70}^o$