In Fig. explain how one can find the breadth of the river without crossing it.
Let AB be the breadth of the river. Mark any point M on the bank which B is situated. Let O be the mid-point of line segment BM. Join AO and produce it to N such that AO = ON. Join M and N.
Now, in △s AOB and NOM, we have
AO = ON [By construction]
∠AOB = ∠MON [Vertically opposite angles]
BO = OM [O is the mid-point of BM]
So, By SAS criterion of congruence
△AOB ≅ △NOM
Therefore, By CPCT AB = MN
Hence, breadth of river is equal to MN.