Question

In fig, find $\angle ACB$ and $\angle A$ and write which of $△ABC$ are equal.

Answer 1

REF.Image.

By linear

angles property

$\angle ACB+{130}^{\circ }={180}^{\circ }$

$\Rightarrow \angle ACB={50}^{\circ }$

As sum of angles of triangle

is ${180}^{\circ },\angle A+80+50=180$

$\Rightarrow \angle A={50}^{\circ },\Rightarrow \angle A=\angle C$