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Question

In fig, if f1,f2 and T are the frictional forces on 2 kg block, 3kg block and tension in the string, respectively, the find their values. Initially before applying the forces, tension in string was zero.
982029_b47fbe5077394a718aa5bca2ce5edb03.png

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Solution

REF. Image.
Force on block 2 kg
T1f1=2a...(1)
Force on block 3 kg
8Tb2=3a...(2)
eq (1)+(2)
T1f1+8Tf2=5a
7=(f1+f2)=5a
___________________
T1f1=2a a = 0
T11=0
T=2N
To cease the motion
bock of 3 kg will
provide 6 N friction
& 2 kg block will provide
1 N friction
So, F2=6N
F1=1N

1173763_982029_ans_c6c2c1890f404e39a6072432a1a975e9.jpg

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