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Question

In fig, if line PQ and RS intersect at point T, such that PRT=40 , RPT=95 and TSQ=75, find SQT. [4 MARKS]

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Solution

Concept: 2 Marks
Application: 2 Marks

In ΔPRT

PTR+PRT+RPT=180 (since the sum of the angles of a triangle is 180)

PTR+40+95=180

PTR+135=180

PTR=180135

PTR=45

QTS=PTR=45 (Vertically Opposite angles)

In ΔTSQ

QTS+TSQ+SQT=180 (since the sum of the angles of a triangle is 180)

SQT+45+75=180

SQT+120=180

SQT=180120

SQT=60


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