In fig. $M = N = 46^{\circ}$ , express $x$ in terms of $a, b$ and $c,$ where a $b$ and $c$ are lengths of $L M, M N$ and $N K$ respectively.

Open in App

Solution

$M = N = 46^{o}$
$△ L M K \sim △ P N K$
By angle $A = A$ similarly
Hence their sides are proportional
$∴ \frac{a}{b + c} = \frac{x}{c}$
$x = \frac{a c}{b + c}$

Suggest Corrections

Similar questions

Q. In the given figure, LM = LN = 46°. Express x in terms of a, b and c where a, b, c are lengths of LM, MN and NK respectively.

In the given figure, $∠ A M N = ∠ M B C = 76^{o}$ . If a, b and c are the lengths of AM, MB and BC respectively then express the length of MN in terms of a, b and c.

Express $l o g 135$ in terms of $m$ and $n$ if $m = l o g 15$ and $n = l o g 3$ .

Q. In three line segments OA, OB and OC points L, M, N respectively are so chosen that LM || AB and MN || BC but neither of L, M, N nor of A, B, C are collinear. Show that LN || AC.

In three line segments OA, OB, and OC, points L, M, N respectively are so chosen that LM || AB and MN || BC but neither of L, M, N nor of A, B, C are collinera. Show that LN || AC.

Join BYJU'S Learning Program

In fig. M=N=46∘ , express x in terms of a, b and c, where a b and c are lengths of LM, MN and NK respectively.

M=N=46o△LMK∼△PNKBy angle A=A similarlyHence their sides are proportional ∴ ab+c=xcx=acb+c

In fig. $M = N = 46^{\circ}$ , express $x$ in terms of $a, b$ and $c,$ where a $b$ and $c$ are lengths of $L M, M N$ and $N K$ respectively.

$M = N = 46^{o}$
$△ L M K \sim △ P N K$
By angle $A = A$ similarly
Hence their sides are proportional
$∴ \frac{a}{b + c} = \frac{x}{c}$
$x = \frac{a c}{b + c}$