Question

In Fig., $$OACB$$ is a quadrant of a circle with centre $$O$$ and radius $$3.5 cm$$. If $$OD = 2 cm$$, find the area of the(i) quadrant $$OACB$$, (ii) Shaded region

Solution

(i)Area of quadrant $$OACB=\dfrac{\text{Area of Circle}}4 =\dfrac{\pi\times r^2}4 = \dfrac{1}{4}\times\dfrac{22}{7}\times3.5\times3.5$$ $$=9.625\,cm^2$$(ii)Area of the shaded region $$=$$ Area of Quadrant $$\,-\,$$Area of $$\triangle BDO$$$$=9.625-\left(\dfrac{1}{2}\times3.5\times2\right)$$$$=\,6.125\,cm^2$$    MathematicsNCERTStandard X

Suggest Corrections

0

Similar questions
View More

Same exercise questions
View More

People also searched for
View More