Question

In fig,$P(5,-3)$ and $Q(3,y)$ are the points of trisection of the line segment joining $A(7,-2)$ and $B(1,-5)$. Then $y$ equals

Answer 1

$x_1=5$ $y_1=1$

$x_2=-3$ $y_2=-5$

$m:n=1:1$

By mid-point formula

$(3,y)=(\frac{5+1}{2},\frac{-3-5}{2})$

$3=\frac{6}{2}$ $y=\frac{-8}{2}$

$y=-4$.