In fig., PA and PB are two tangents drawn from an external point P to a circle with centre C and radius 4 cm. If PA ⊥ PB, then the length of each tangent is:
4 cm
AP ⊥ PB (Given)
CA ⊥ AP, CB ⊥ BP (Since radius is perpendicular to tangent)
AC = CB = radius of the circle
Therefore, APBC is a square having side equal to 4 cm.
Therefore, length of each tangent is 4 cm.