In fig., PA and PB are two tangents drawn from an external point P to a circle with centre C and radius 4cm. If PA⊥PB, then the length of each tangent is:
A
3cm
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B
4cm
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C
5cm
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D
6cm
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Solution
The correct option is A4cm Given that PA and PB are two tangent drawn from an external point P.
And a circle with center C and radius 4 cm and PA⊥PB
Join center C with A and B
Given PA and PB are tangent of circle.
Then PA⊥CA and PB⊥CB
Therefore, ∠CAP=900 and ∠CBP=900
But given, ∠APB=900
Therefore, ∠CBA=900
Therefore, quadrilateral ABCD has all angles equal i.e. 900