In Fig. PQ > PR. QS and RS are the bisectors of ∠Q and ∠R respectively
Prove that SQ>SR
In △ PQR, we have
PQ > PR [Given]
⇒ ∠PRQ > ∠PQR [Angle opposite to largest side of a triangle is greater]
⇒ ∠PRQ > ∠PQR
⇒ ∠SRQ > ∠SQR
[∵ RS and QS are bisectors of ∠PRQ are ∠PQR respectively]
⇒ SQ > SR
[∵ Side opp. to greater angle is larger]