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Question

In Fig shows a uniform metre rule of weight W supported on a fulcrum at the 60 cm mark by applying the effort E at the 90 cm mark.

(a) State with reason whether the weight W of the rule is greater than, less than or equal to the effort E.

(b) Find the mechanical advantage in an ideal case.

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Solution

(a)
Let M be load.
∴ Load arm = 90 – 60 = 30 cm
Since wt. of scale will act at centre of gravity of scale which is the midpoint of the scale.
∴ Effort arm = 60 – 50 = 10 cm
Let wt. of scale be W
By principal of moments L × dL = E × dE
M × 30 = W × 10
W = 3M
∴ Since weight of scale is three times that of M.
∴ Weight of scale is greater than weight of M.

(b)
MA=efort arm / load arm
=10/30=1/3

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