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Question

In fig sides QP and RQ of ΔPQR are produced to .the points S and T respectively. If SPR=105PQT=110 then find PRQ.
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A
35o
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B
70o
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C
105o
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D
140o
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Solution

The correct option is A 35o
SPR+RPQ=180 (Angles on a straight line)
105+RPQ=180
RPQ=75
TQP+PQR=180 (Angles on a straight line)
110+PQR=180
PQR=70
Now, in PQR
PQR+PRQ+QPR=180 (Angles of a triangle)
70+75+QPR=180
QPR=35

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