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Question

In fig, the line segment XY is parallel to side AC of ABC and it divides the triangle into two parts of equal areas. Find the ratio AXAB

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Solution

We are given that XY || AC.

1 = 3 and 2 = 4 [ corresponding angles ]

BXY ~ BAC [ AA similarity ]

ar (BXY)ar (BAC)=(BX)2(BA)2 [ By theorem] ..... (i)

Also, we are given that

ar ( BXY ) = ar ( BAC ) ar(BXY)ar(BAC)=(12)12 ....(ii)


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