In fig., △ABC is circumscribing a circle. Find the length (in cm) of BC
As the lengths of tangents drawn from an external point to a circle are equal,
AR = AQ = 4
CQ = CA – AQ
CQ = 11 – 4
CQ = 7
Now CP = CQ
Hence CP = 7
Now BP = BR
Hence BP = 3
BC = BP + CP
BC = 3 + 7
BC = 10 cm