In fig x-30- the value of 6 Y -3 X isA- 180-B- 60-C- 150-D- 120-

The correct option is C x = 30^∘, 2x = 60^∘ 2x + 3y = 180^∘ (Linear Angle Property) 60 + 3y = 180^∘ 3y = 120^∘ Y = 40^∘ The value of 6Y 3X = 150^∘ ...

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Byju's Answer

Standard VIII

Mathematics

Exterior Angle Theorem

In fig x=30∘ ...

Question

In fig $x =$ $30^{\circ}$ the value of $(6 y - 3 x)$ is

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Solution

The correct option is C ( $150^{\circ}$ )
Given $x =$ $30^{\circ}$ $\Rightarrow 2 x =$ $60^{\circ}$

Since, $2 x + 3 y =$ $180^{\circ}$ as they form linear angle.

$\Rightarrow 60 + 3 y =$ $180^{\circ}$

$3 y =$ $120^{\circ}$

$∴ y =$ $40^{\circ}$

Thus, the value of $6 y - 3 x = 6 (40) - 3 (30)$
$= 240 - 90$
$∴ 6 y - 3 x = 150^{\circ}$

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In fig x= 30∘ the value of (6y–3x) is

The correct option is C (150∘)Given x= 30∘ ⇒2x= 60∘ Since, 2x+3y=180∘ as they form linear angle. ⇒60+3y= 180∘ 3y= 120∘ ∴y= 40∘ Thus, the value of 6y−3x=6(40)−3(30) =240−90∴6y−3x=150∘

In fig $x =$ $30^{\circ}$ the value of $(6 y - 3 x)$ is