In Fig. X and Y are two points on equal sides AB and AC of a ΔABC such that AX = AY. Prove that XC = YB. [2 MARKS]
Concept : 1 Mark
Proof : 1 Mark
In Δs AXC and AYB, we have
AX = AY [Given]
∠A = ∠A [Common angle]
AC = AB [Given]
So,
ΔAXC ≅ ΔAYB [SAS congruence criterion]
⇒ XC = YB [Since corresponding parts of congruent triangles are equal]