In Figure 1, the length of ¯¯¯¯¯¯¯¯¯¯WZ is 3a+15 and the length of ¯¯¯¯¯¯¯¯¯¯WX is 7a+5. If Y is the midpoint of ¯¯¯¯¯¯¯¯¯XZ, calculate the length of ¯¯¯¯¯¯¯¯¯¯WY.
A
5+4a
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5−2a
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
25+4a
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
20+5a
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
10+5a
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is E10+5a
Given that WZ=3a+15 , WX=7a+5
Therefore, we get XZ=WZ−WX=3a+15−7a−5=10−4a
Given that Y is midpoint of XZ, therefore we get ⇒XY=XZ2=(10−4a)2=5−2a ⇒WY=WX+XY