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Question

In Figure 1, the length of ¯¯¯¯¯¯¯¯¯¯WZ is 3a+15 and the length of ¯¯¯¯¯¯¯¯¯¯WX is 7a+5. If Y is the midpoint of ¯¯¯¯¯¯¯¯¯XZ, calculate the length of ¯¯¯¯¯¯¯¯¯¯WY.
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A
5+4a
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B
52a
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C
25+4a
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D
20+5a
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E
10+5a
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Solution

The correct option is E 10+5a
Given that WZ=3a+15 , WX=7a+5
Therefore, we get XZ=WZWX=3a+157a5=104a
Given that Y is midpoint of XZ, therefore we get
XY=XZ2=(104a)2=52a
WY=WX+XY
=7a+5+52a
=10+5a

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