Question

In Figure 4, two triangles ABC and DBC are on the same base BC in which ∠A = ∠D = 90°. If CA and BD meet each other at E, show that AE ✕ CE = BE ✕ DE.

Answer 1

Given that, there are two triangles ABC and DBC are on the same base BC in which
∠A = ∠D = 90°. If CA and BD meet each other at E, then we have to prove that AE × CE = BE × DE

The following figure is given

From the above figure, we can easily see thatare similar triangles, therefore we can use the property of similar triangle.

Hence