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Byju's Answer

Standard IX

Physics

Second Law of Motion

In figure 5-E...

Question

In figure (5−E11), m₁ = 5 kg, m₂ = 2 kg and F = 1 N. Find the acceleration of either block. Describe the motion of m₁ if the string breaks but F continues to act.

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Solution

Let the acceleration of the blocks be a.
The free-body diagrams for both the blocks are shown below:

From the free-body diagram,
m₁a = m₁g + F − T ...(i)

Again, from the free-body diagram,
m₂a = T − m₂g − F ...(ii)

Adding equations (i) and (ii), we have:
$a = g \frac{m_{1} - m_{2}}{m_{1} + m_{2}}$
$\Rightarrow a = \frac{3 g}{7} = \frac{29.4}{7} = 4.2 m / s^{2}$
Hence, acceleration of the block is 4.2 m/s².

After the string breaks, m₁ moves downward with force F acting downward. Then,

m₁a = F + m₁g
5a = 1 + 5g
$\Rightarrow a = \frac{5 g + 1}{5} = g + 0.2 m / s^{2}$

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In figure (5−E11), m1 = 5 kg, m2 = 2 kg and F = 1 N. Find the acceleration of either block. Describe the motion of m1 if the string breaks but F continues to act. Figure

In figure (5−E11), m₁ = 5 kg, m₂ = 2 kg and F = 1 N. Find the acceleration of either block. Describe the motion of m₁ if the string breaks but F continues to act.

Figure