CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

In figure, a crate slides down an inclined right angled trough. Acceleration of the crate is

A
2.1 m/s2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2.5 m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2.7 m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2.9 m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2.1 m/s2
FBD of crate:


Here,
N= Normal reaction on the crate applied by trough,
f= Friction force on the crate opposite to the sliding motion.

Balancing forces for front view of the crate, we have,

mgcos45=N2+N2

2N=mg2

N=mg2

Now, balancing forces for side view, we have,

mgsin452f=ma......(1)

where, a= acceleration of the crate parallel to the inclined plane in the downwards direction.
f=μN=0.5N=0.5mg2

Substituting the values in (1), we have,

mgsin452μN=ma

ma=mg×122×0.5×mg2

a=g20.5g

a=0.710.5g

a=0.21g

a=0.21×10

a=2.1 m/s2

Hence, option (a) is correct answer.

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon