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Question

In figure, AP,AQ and BC are tangents of the circle with centre O. If AB=5 cm,AC=6 cm and BC=4 cm, then the length of AP( in cm) is

A
9
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B
15
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C
10
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D
7.5
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Solution

The correct option is D 7.5
Due to tangents from external points, BP=BR,CR=CQ, and AP=AQ
Perimeter of ABC,
AB+BC+AC=AB+BR+RC+AC5+4+6=AB+BP+CQ+AC15=AP+AQ15=2AP
Thus AP=152=7.5 cm

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