In figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. Find the area of the shaded region (in cm2).
Area of quadrant = 90360×π×14×14 = 153.94 cm2
Area of △ABC = 0.5 x 142 = 98 cm2
The diameter = 14 × √2 = 19.8 cm.
Area of semi-circle = 0.5 π×9.92 = 153.95 cm2
The area of segment = 153.94 - 98 = 55.94cm2
The required area = 153.95 - 55.94 = 98.01cm2.