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Question

In figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. Find the area of the shaded region (in cm2).

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Solution

Area of quadrant = 90360×π×14×14 = 153.94 cm2

Area of ABC = 0.5 x 142 = 98 cm2

The diameter = 14 × 2 = 19.8 cm.

Area of semi-circle = 0.5 π×9.92 = 153.95 cm2

The area of segment = 153.94 - 98 = 55.94cm2

The required area = 153.95 - 55.94 = 98.01cm2.


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