Question

In figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. Find the area of the shaded region.

• A. 98.01
• B. 98.01 $m^2$
• C. 89.01 $c{m}^2$
• D. 9801 $m{m}^2$

Answer 1

Answer: (A), (D)

The correct options are
A

98.01

D 9801 $m{m}^2$

Area of quadrant = $\frac{90}{360}\times \pi \times 14\times 14$ = 153.94 $c{m}^2$

Area of $△ABC$ = 0.5 x ${14}^2$ = 98 $c{m}^2$

The diameter = 14 × $\sqrt{2}$ = 19.8 cm.

Area of semi-circle = 0.5 $\pi \times {9.9}^2$ = 153.95 $c{m}^2$

The area of segment = 153.94 - 98 = 55.94$c{m}^2$

The required area = 153.95 - 55.94 = 98.01$c{m}^2$.