In figure- ABCD is a parallelogram Prove that DQDP-AQDC

∠ DPC=∠ BPQ(Vert. Opp) ∠ DCP=∠ PBQ(Int. Alt) ∠ CDP=∠ BQP(Int. Alt) By AAA criteria #160; Δ PCD∼Δ PBQ Since The triangles are similar th ...

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Opposite Sides of a Parallelogram Are Equal

In figure, ...

Question

In figure, $A B C D$ is a parallelogram
Prove that $\frac{D Q}{D P} = \frac{A Q}{D C}$

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Solution

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A B C D

\frac{D P}{P Q} = \frac{D C}{B Q}

In the adjoining figure ABCD is a parallelogram. ‘P’ is a point on BC, DP and AB are produced meet at L. Prove that DP : PL = DC : BL.

In the given figure, AB = AC. Prove that :

(i) DP= DQ

(ii) AP = AQ

(iii) AD bisects angle A

\frac{D P}{P L} = \frac{D C}{B L}

\frac{D L}{D P} = \frac{A L}{D C}

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