In figure, ABCD is a trapezium in which $A B ∥ E F ∥ D C$ . The length of AE is :

2 cm

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3 cm

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4 cm

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7 cm

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Solution

The correct option is C 3 cm
Let $A E = x c m s o, E D = (9 - x)$ cm.
By similarity, $\frac{B F}{B C} = \frac{A E}{A D} ⟹ \frac{2}{6} = \frac{x}{9} ⟹ x = 3 c m$ .
Hence, $A E = 3 c m$

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In figure, ABCD is a trapezium in which AB∥EF∥DC. The length of AE is :

The correct option is C 3 cmLet AE=x cm so,ED=(9−x) cm.By similarity, BFBC=AEAD⟹26=x9⟹x=3cm.Hence, AE=3cm

In figure, ABCD is a trapezium in which $A B ∥ E F ∥ D C$ . The length of AE is :

The correct option is C 3 cm
Let $A E = x c m s o, E D = (9 - x)$ cm.
By similarity, $\frac{B F}{B C} = \frac{A E}{A D} ⟹ \frac{2}{6} = \frac{x}{9} ⟹ x = 3 c m$ .
Hence, $A E = 3 c m$