In figure, AD = BC, then prove that AC = BD
In figure, we have
AD= BC ….(1)
By the application of Euclid’s axiom when we add CD from both side of (1) , the whole part sides of (1) are equal .
AC+CD= BD+CD
AC= BD
In the given figure, ∠ACB=90o and CD⊥AB.
Prove that BC2AC2=BDAD.
In the given figure, ABC is a triangle in which ∠ABC < 90° and AD ⊥ BC. Prove that AC2 = AB2 + BC2 − 2BC.BD.